{"id":2763,"date":"2024-03-31T08:42:20","date_gmt":"2024-03-31T00:42:20","guid":{"rendered":"https:\/\/www.aqwu.net\/wp\/?p=2763"},"modified":"2024-03-31T11:38:49","modified_gmt":"2024-03-31T03:38:49","slug":"%e4%b8%80%e9%ab%98%e4%b8%ad%e7%9a%84%e9%ab%98%e8%80%83%e6%a8%a1%e6%8b%9f%e5%a4%a7%e9%a2%98","status":"publish","type":"post","link":"https:\/\/www.aqwu.net\/wp\/?p=2763","title":{"rendered":"\u4e00\u9ad8\u4e2d\u7684\u9ad8\u8003\u6a21\u62df\u5927\u9898"},"content":{"rendered":"\n<p>\u8fd9\u636e\u8bf4\u662f\u6cb3\u5357\u4e00\u9ad8\u4e2d\u6a21\u62df\u8003\u8bd5\u7684\u6700\u540e\u5927\u9898\uff1a<\/p>\n\n\n\n<p>\u5728\u5bc6\u7801\u5b66\u9886\u57df,\u6b27\u62c9\u51fd\u6570\u662f\u975e\u5e38\u91cd\u8981\u7684,\u5176\u4e2d\u6700\u8457\u540d\u7684\u5e94\u7528\u5c31\u662f\u5728<em><strong>RSA<\/strong><\/em>\u52a0\u5bc6\u7b97\u6cd5\u4e2d\u7684\u5e94\u7528.\u8bbe <em>p,q<\/em> \u662f\u4e24\u4e2a\u6b63\u6574\u6570,\u82e5 <em>p,q<\/em> \u7684\u6700\u5927\u516c\u7ea6\u6570\u662f1,\u5219\u79f0 <em>p,q<\/em> \u4e92\u7d20,\u5bf9\u4e8e\u4efb\u610f\u6b63\u6574\u6570 <em>n<\/em> ,\u6b27\u62c9\u51fd\u6570\u662f\u4e0d\u8d85\u8fc7 <em>n<\/em> \u4e14\u4e0e <em>n<\/em> \u4e92\u7d20\u7684\u6b63\u6574\u6570\u7684\u4e2a\u6570,\u8bb0\u4e3a \u03c6(n).<\/p>\n\n\n\n<p>(1)\u8bd5\u6c42 \u03c6(3),\u03c6(9),\u03c6(7),\u03c6(21)\u7684\u503c;<\/p>\n\n\n\n<p>(2)\u8bbe <em>n<\/em> \u662f\u4e00\u4e2a\u6b63\u6574\u6570 <em>p,q<\/em> \u662f\u4e24\u4e2a\u4e0d\u540c\u7684\u7d20\u6570,\u8bd5\u6c42\u03c6(3<sup><em>n<\/em><\/sup>), \u03c6(pq)\u4e0e \u03c6(p)\u548c\u03c6(q)\u7684\u5173\u7cfb<\/p>\n\n\n\n<p>(3)RSA\u7b97\u6cd5\u662f\u4e00\u79cd\u975e\u5bf9\u79f0\u52a0\u5bc6\u7b97\u6cd5,\u5b83\u4f7f\u7528\u4e86\u4e24\u4e2a\u4e0d\u540c\u7684\u5bc6\u94a5:\u516c\u94a5\u548c\u79c1\u94a5,\u5177\u4f53\u800c\u8a00:<br>\u2460\u51c6\u5907\u4e24\u4e2a\u4e0d\u540c\u7684\u3001\u8db3\u591f\u5927\u7684\u7d20\u6570<em>p,q<\/em>;<br>\u2461\u8ba1\u7b97<em>n=pq<\/em>,\u6b27\u62c9\u51fd\u6570 \u03c6(n);<br>\u2462\u6c42\u6b63\u6574\u6570k,\u4f7f\u5f97kq\u9664\u4ee5\u03c6(n)\u7684\u4f59\u6570\u662f1;<br>\u2463\u5176\u4e2d<em>(n,q)<\/em>\u79f0\u4e3a\u516c\u94a5,<em>(n,k)<\/em>\u79f0\u4e3a\u79c1\u94a5.<br>\u5df2\u77e5\u8ba1\u7b97\u673a\u5de5\u7a0b\u5e08\u5728\u67d0 <strong><em>RSA<\/em><\/strong> \u52a0\u5bc6\u7b97\u6cd5\u4e2d\u516c\u5e03\u7684\u516c\u94a5\u662f(187,17).\u82e5\u6ee1\u8db3\u9898\u610f\u7684\u6b63\u6574\u6570k\u4ece\u5c0f\u5230\u5927\u6392\u5217\u5f97\u5230\u4e00\u5217\u6570\u8bb0\u4e3a\u6570\u5217{<em>b<sub>n<\/sub><\/em>)\uff0c\u6570\u5217{<em>c<sub>n<\/sub><\/em>)\u6ee1\u8db380<em>c<sub>n<\/sub><\/em>=<em>b<sub>n<\/sub><\/em>\u534147,\u6c42\u6570\u5217{tanc<sub>n<\/sub>\u00b7tanc<sub>n+1<\/sub>}\u7684\u524d\u9879\u548cT<sub>n<\/sub><\/p>\n\n\n\n<p><strong>\u7b54\u6848\u5982\u4e0b<\/strong>\uff1a<\/p>\n\n\n\n<p><strong>(1)<\/strong> \u5957\u516c\u5f0f\uff1a<em>\u03c6(p<sup>k<\/sup>)<\/em> = <em>p<sup>k<\/sup><\/em> &#8211; <em>p<sup>k<\/sup><\/em><sup>-1<\/sup> (p\u4e3a\u8d28\u6570\uff0ck\u4e3a\u5927\u4e8e\u7b49\u4e8e1\u7684\u6574\u6570)<\/p>\n\n\n\n<p> \u2460 \u03c6(3)= 3<sup>1<\/sup> &#8211; 3<sup>0<\/sup> = 3 &#8211; 1 = 2 <strong>(1,2)<\/strong><\/p>\n\n\n\n<p> \u2461 \u03c6(9) = \u03c6(3<sup>2<\/sup>) = 3<sup>2<\/sup> -3<sup>2-1<\/sup> = 9-3 = 6 <strong>(1,2,4,5,7,8)<\/strong><\/p>\n\n\n\n<p> \u2462 \u03c6(7) = 7<sup>1<\/sup> &#8211; 7<sup>0<\/sup> = 7 &#8211; 1 = 6 <strong>(1,2,3,4,5,6)<\/strong><\/p>\n\n\n\n<p> \u2463 \u03c6(21) = \u03c6(3*7) = \u03c6(3) * \u03c6(7) = 2 * 6 = 12 <strong>(1,2,4,5,8,10,11,13,16,17,19,20)<\/strong><\/p>\n\n\n\n<p><strong>(2)<\/strong><\/p>\n\n\n\n<p> \u2460 \u03c6(3<sup><em>n<\/em><\/sup>) = 3<sup>n<\/sup> &#8211; 3<sup>n-1<\/sup> = 3<sup>n<\/sup>(1-1\/3)= 2 * 3<sup>n-1<\/sup><\/p>\n\n\n\n<p>    \u9a8c\u8bc1\uff0c\u5982\u679cn = 1, \u03c6(3<sup><em>1<\/em><\/sup>) = 2 * 3<sup>0<\/sup> = 2<\/p>\n\n\n\n<p>         \u5982\u679c n = 2, \u03c6(3<sup><em>2<\/em><\/sup>) = 2 * 3<sup>2-1<\/sup> = 2 * 3<sup>1<\/sup> = 6<\/p>\n\n\n\n<p>         \u5982\u679c n = 3, \u03c6(3<sup><em>3<\/em><\/sup>) = 2 * 3<sup>3-1<\/sup> = 2 * 3<sup>2<\/sup> = 18 <strong>(1,2,4,5,7,8,10,11,13,14,16,17,19,20,22,23,25,26)<\/strong><\/p>\n\n\n\n<p> \u2461 \u03c6(pq) = \u03c6(p)* \u03c6(q)<\/p>\n\n\n\n<p><strong>(3) <\/strong>\u56e0\u4e3a n = 187, q = 17 \u5f97 p = 11<\/p>\n\n\n\n<p>    \u03c6(187) = \u03c6(17) * \u03c6(11) = 16 * 10 = 160<\/p>\n\n\n\n<p><strong>    \u6c42 b<sub>n<\/sub><\/strong><\/p>\n\n\n\n<p>    17k % 160 <em>\u2261<\/em> 1<\/p>\n\n\n\n<p>    17k + 160y = 1 <\/p>\n\n\n\n<p>    \u6c42\u4e24\u4e2a\u6570\u6700\u5927\u516c\u7ea6\u6570\u7684\u8f97\u8f6c\u76f8\u9664\u6cd5<\/p>\n\n\n\n<p>    160 \/ 17 = 9 &#8230; 7, \u6240\u4ee5 7 = 160 &#8211; 17 * 9<\/p>\n\n\n\n<p>    17 \/ 7 = 2 &#8230; 3, \u6240\u4ee5 3 = 17 &#8211; 7 * 2<\/p>\n\n\n\n<p>    7 \/ 3 = 2 &#8230; 1\uff0c \u6240\u4ee5 1 = 7 &#8211; 3 * 2<\/p>\n\n\n\n<p>    \u6240\u4ee5 1 = 7 &#8211; 3 * 2 = 7 &#8211; (17 &#8211; 7 * 2) * 2 <\/p>\n\n\n\n<p>        = 7 + 4 * 7 &#8211; 17 * 2  =  5 * 7 -17 * 2 <\/p>\n\n\n\n<p>        = 5 * (160 &#8211; 17 * 9) -17 * 2 + <\/p>\n\n\n\n<p>        = 5 * 160 -17 * (2 + 45)<\/p>\n\n\n\n<p>        = 5 * 160 -17 * 47 <\/p>\n\n\n\n<p>    \u5f97\uff0c5 * 160 &#8211; 17 * 47 = 1<\/p>\n\n\n\n<p>    \u5f97 y = 5, k = -47<\/p>\n\n\n\n<p>    \u8981\u6c42k \u662f\u6b63\u6574\u6570\uff0c\u53ef\u4ee5<\/p>\n\n\n\n<p>    -17 * 47 = 1 + (- 5 * 160)<\/p>\n\n\n\n<p>    \u4e24\u8fb9\u52a0\u4e0a 17 * 160<\/p>\n\n\n\n<p>    17 * (160 &#8211; 47) = 1 + (17 &#8211; 5) * 160<\/p>\n\n\n\n<p>    17 * 113 = 1 + 12 * 160 <\/p>\n\n\n\n<p>    \u7b2c\u4e00\u4e2a k\u503c \u662f 113<\/p>\n\n\n\n<p>    \u6c42\u7b2c\u4e8c\u4e2ak\u503c\uff0c\u7b2c\u4e00\u4e2ak\u503c + \u03c6(187) = 113 + 160 = 273<\/p>\n\n\n\n<p>    \u6c42\u7b2c\u4e09\u4e2ak\u503c\uff0c\u662f\u7b2c\u4e8c\u4e2ak\u503c + \u03c6(187) = 273 + 160 = 433<\/p>\n\n\n\n<p>    \u6c42\u7b2c\u56db\u4e2ak\u503c\uff0c\u662f\u7b2c\u4e09\u4e2ak\u503c + \u03c6(187) = 433+ 160 = 593<\/p>\n\n\n\n<p>    b<sub>n<\/sub> = b<sub>n-1<\/sub> + 160<\/p>\n\n\n\n<p>    b<sub>n<\/sub> = 113 + (n -1) * 160 = 160n &#8211; 47<\/p>\n\n\n\n<p><strong>   \u6c42 c<sub>n<\/sub><\/strong><\/p>\n\n\n\n<p>     c<sub>n<\/sub> = (b<sub>n<\/sub> + 47 = 160n &#8211; 47 + 47)\/80 = 160n \/ 80 = 2n<\/p>\n\n\n\n<p>   <strong> \u6c42 <em>T<sub>n<\/sub><\/em><\/strong><\/p>\n\n\n\n<p>    tanc<sub>n<\/sub>\u00b7tanc<sub>n+1<\/sub> = tan2n * tan2(n+1)<\/p>\n\n\n\n<p>    tan(2)= tan((2n+2)-2n)<\/p>\n\n\n\n<p>    tan(n) = tan[2(<em>n<\/em>+1)]\u2212tan(2<em>n<\/em>)\u200b\/(1+tan[2(<em>n<\/em>+1)]tan(2<em>n<\/em>))<\/p>\n\n\n\n<p><em>    T<sub>n<\/sub><\/em>\u200b= tan[2(<em>n<\/em>+1)]\u2212tan(2)\u200b\/(tan(2)\u22121)<\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u8fd9\u636e\u8bf4\u662f\u6cb3\u5357\u4e00\u9ad8\u4e2d\u6a21\u62df\u8003\u8bd5\u7684\u6700\u540e\u5927\u9898\uff1a 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